11th | Depreciation | Question No. 9 To 12 | Ts Grewal Solution 2024-2025

Question 9:

On 1st April, 2022, Harish traders purchased 5 machines for `60,000 each. On 1st April, 2022, one of the machine was sold at a loss of `8,000. On 1st July, 2023, second machine was sold at a loss of `12,500. A new machine was purchased for `1,00,000 on 1st October, 2023.
Prepare Machinery Account for 4 years, assuming accounts are closed on 31st March each year and depreciation is charged @ 10% per annum as per Straight Line Method.

Answer:

Dr.

Machinery A/c

Cr.

Date

Particulars

 (`)

Date

Particulars

 (`)

2022

 

 

2023

 

 

April 01

To Cash/Bank A/c (60,000 × 5)

3,00,000

March 31

By Depreciation A/c (3,00,000 × 10/100)

30,000

 

 

 

March 31

By balance c/d

2,70,000

 

 

 

 

 

 

 

 

3,00,000

 

 

3,00,000

2023

 

 

2024

 

 

April 01

To balance b/d

2,70,000

March 31

By Depreciation A/c (3,00,000 × 10/100)

30,000

 

 

 

March 31

By balance c/d

2,40,000

 

 

 

 

 

 

 

 

2,70,000

 

 

2,70,000

2024

 

 

2024

 

 

April 01

To balance b/d

2,40,000

April 01

By Bank A/c (WN1)

40,000

 

 

 

April 01

By Profit & Loss A/c (Loss on sale)

8,000

 

 

 

2025

 

 

 

 

 

March 31

By Depreciation A/c (2,40,000 × 10/100)

24,000

 

 

 

 

(On remaining machinery)

 

 

 

 

March 31

By balance c/d

1,68,000

 

 

 

 

 

 

 

 

2,40,000

 

 

2,40,000

2025

 

 

2025

 

 

April 01

To balance c/d

1,68,000

July 1

By Depreciation A/c (6,000 × 3/12)

1,500

Oct.01

To Cash/Bank A/c

1,00,000

July 1

By Bank A/c (WN2)

28,000

 

 

 

July 1

By Profit & Loss A/c (Loss on Sale)

12,500

 

 

 

2026

 

 

 

 

 

March 31

By Depreciation A/c (On remaining

23,000

 

 

 

 

Machinery)

 

 

 

 

 

[(1,80,000 × 10/100) +

 

 

 

 

 

(1,00,000 × 10/100 × 6/12)]

 

 

 

 

March 31

By balance c/d

2,03,000

 

 

 

 

 

 

 

 

2,68,000

 

 

2,68,000

 

 

 

 

 

 


Working Notes:

1) Calculation of Sale proceeds from Machinery sold on 1st April, 2024

Book Value of the Machine as on 1st April, 2024

=

(Total opening balance of Machinery on this date/5)

 

=

 `(2,40,000/5) = `48,000

Loss on Sale of Machinery

=

 `8,000

Sale proceeds from the Machinery

=

Book Value of the Machine as on 1st April, 2024 – Loss on Sale

 

=

 `(48,000 – 8,000) = `40,000

 

 

 

2) Calculation of Sale proceeds from Machinery sold on 1st July 2025

Book Value of the Machine as on 1st July, 2025

=

[(Total opening balance of Machinery on this date/4-Depreciation]

 

=

 `[(1,68,000/4) – 1,500] = `40,500

Loss on Sale of Machinery

=

 `12,500

Sale proceeds from the Machinery

=

Book Value of the Machine as on 1st July, 2025 – Loss on Sale

 

=

 `(40,500 – 12,500) = `28,000

Question 10:

On 1st April, 2020, Gurman toys purchased a machine for `2,40,000 and spent `10,000 on its erection. On 1st October, 2020 an additional machinery costing `1,00,000 was purchased. On 1st October, 2022, the machine purchased on 1st April, 2020 was sold for `1,43,000 and on the same date, a new machine was purchased at cost of `2,00,000.
Show the Machinery Account for the first four financial years after charging Depreciation at 5% p.a. by the Straight Line Method.

Answer:

Machinery Account

Dr.

 

Cr.

Date

Particulars

J.F.

 (`)

Date

Particulars

J.F.

 (`)

2020

 

 

 

2021

 

 

 

April 01

Bank (M1)

 

2,50,000

March 31

Depreciation

 

 

Oct. 01

Bank (M2)

 

1,00,000

 

M1

12,500

 

 

 

 

 

 

 

M2 (6 Months)

2,500

 

15,000

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

M1

2,37,500

 

 

 

 

 

 

 

M2

97,500

 

3,35,000

 

 

 

3,50,000

 

 

 

3,50,000

2021

 

 

 

2022

 

 

 

April 01

Balance b/d

 

 

March 31

Depreciation

 

 

 

M1

2,37,500

 

 

 

M1

12,500

 

 

 

M2

97,500

 

3,35,000

 

M2

5,000

 

17,500

 

 

 

 

 

 

 

 

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

M1

2,25,000

 

 

 

 

 

 

 

M2

92,500

 

3,17,500

 

 

 

3,35,000

 

 

 

3,35,000

2022

 

 

 

2022

 

 

 

April 01

Balance b/d

 

 

Oct. 01

Depreciation (for 6 months)

 

6,250

 

M1

2,25,000

 

 

Oct. 01

Bank (M1 sold)

 

1,43,000

 

M2

92,500

 

3,17,500

Oct. 01

Profit and Loss (loss on sale)

 

75,750

 

 

 

 

 

2023

 

 

 

July 01

Bank (M3)

 

2,00,000

March 31

Depreciation

 

 

 

 

 

 

 

M2

5,000

 

 

 

 

 

 

 

M3 (for 6 months)

5,000

 

10,000

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

M2

87,500

 

 

 

 

 

 

 

M3

1,95,000

 

2,82,500

 

 

 

5,17,500

 

 

 

5,17,500

2023

 

 

 

2024

 

 

 

April 01

Balance b/d

 

 

March 31

Depreciation

 

 

 

M2

87,500

 

 

 

M2

5,000

 

 

 

M3

1,95,000

 

2,82,500

 

M3

10,000

 

15,000

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

M2

82,500

 

 

 

 

 

 

 

M3

1,85,000

 

2,67,500

 

 

 

2,82,500

 

 

 

2,82,500

 

 

 

 

 

 

 

 

 

Working Notes:

1. Calculation of Deprecation  

Machine 1= 2,50,000×5/100= `12,500 p.a.

Machine 2= 1,00,000×5/100= `5,000 p.a.

Machine 3= 2,00,000×4/100= `10,000 p.a.

 

2. Calculation of profit or loss on sale of Machine

Particulars

 (`)

Book Value on April 01, 2022

2,25,000

Less: Deprecation for six month

(6,250)

Book Value on Oct. 01, 2022

2,18,750

Less: Sale Proceeds

(1,43,000)

Loss on Sale of Machine

75,750

 

Question 11:

A Van was purchased on 1st April, 2020 for `60,000 and `5,000 was spent on its repair and registration. On 1st October, 2021 another van was purchased for `70,000. On 1st April, 2022, the first van purchased on 1st April, 2020 was sold for `45,000 and a new van costing `1,70,000 was purchased on the same date. Show the Van Account from 2020-21 to 2022-23 on the basis of Straight Line Method, if the rate of Depreciation charged is 10% p.a. Assume that books are closed on 31st March every year.

Answer:

Van Account 

Dr.

 

Cr.

Date

Particulars

J.F.

 (`)

Date

Particulars

J.F.

 (`)

2020

 

 

 

2021

 

 

 

April 01

Bank A/c (I)

 

65,000

March 31

Depreciation A/c (I)

 

6,500

 

 

 

 

March 31

Balance c/d (I)

 

58,500

 

 

 

65,000

 

 

 

65,000

2021

 

 

 

2022

 

 

 

April 01

Balance b/d (I)

 

58,500

March 31

Depreciation A/c

 

 

Oct. 01

Bank A/c (II)

 

70,000

 

(I)

6,500

 

 

 

 

 

 

 

(II)

(for 6 month)

3,500

 

10,000

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

(I)

52,000

 

 

 

 

 

 

 

(II)

66,500

 

1,18,500

 

 

 

1,28,500

 

 

 

1,28,500

2022

 

 

 

2022

 

 

 

April 01

Balance b/d

 

 

April 01

Bank A/c (I)

 

45,000

 

(I)

52,000

 

 

April 01

Profit and Loss A/c (Loss on Sale)

 

7,000

 

 

 

 

 

2023

 

 

 

 

(II)

66,500

 

1,18,500

March 31

Depreciation A/c

 

 

April 01

Bank A/c (III)

 

1,70,000

 

(II)

7,000

 

 

 

 

 

 

 

(III)

17,000

 

24,000

 

 

 

 

March 31

Balance c/d

 

 

 

 

 

 

 

(II)

59,500

 

 

 

 

 

 

 

(III)

1,53,000

 

2,12,500

 

 

 

2,88,500

 

 

 

2,88,500

 

 

 

 

 

 

 

 

Working Notes

1. Calculation of Annual Depreciation

Maruti  Van (1) = 65,000×10/100= `6,500

Maruti  Van (1I) = 70,000×10/100= `7,000

Maruti  Van (1II) =1,70,000×10/100= `17,000

2. Calculation of profit or loss on sale of Van (I)

 

Particulars

 (`)

Book Value on Apr. 01, 2022

52,000

Less: Sale of Van

(45,000)

Loss on Sale of Van

7,000

 

 

Question 12:

On 1st April, 2010, Plant and Machinery was purchased for `1,20,000. New machinery was purchased on 1st October, 2010 for `50,000 and on 1st July, 2011, for `25,000. On 1st January, 2013, a machinery of the original value of `20,000 which was included in the machinery purchased on 1st April, 2010, was sold for `6,000. Prepare Plant and Machinery A/c for three years after providing depreciation at 10% p.a. on Straight Line Method. Accounts are closed on 31st March every year. (KVS)

Answer

Machinery Account 

Dr.

 

Cr.

Date

Particulars

J.F.

 (`)

Date

Particulars

J.F.

 (`)

2010

 

 

 

2011

 

 

 

April 01

Bank A/c (M1)

 

1,20,000

Mar.31

Depreciation A/c

 

 

Oct. 01

Bank A/c (M2)

 

50,000

 

M1 – 12,000

 

 

 

 

 

 

 

(WN3) M2 – 2,500

 

14,500

 

 

 

 

Mar.31

Balance c/d

 

 

 

 

 

 

 

M1 – 1,08,000

 

 

 

 

 

 

 

M2 – 47,500

 

1,55,500

 

 

 

1,70,000

 

 

 

1,70,000

2011

 

 

 

2012

 

 

 

April 01

Balance B/d

 

 

Mar.31

Depreciation A/c

 

 

 

M1 – 1,08,000

 

 

M1 – 12,000

 

 

 

M2 – 47,500

1,55,500

 

M2 – 5,000 

 

 

 

 

 

 

(WN4) M3-1,875

 

18,875

July 01

Bank A/c (M3)

 

25,000

Mar.31

Balance c/d

 

 

2012

 

 

 

 

M1 – 96,000

 

 

 

 

 

 

 

M2 – 42,500

 

 

 

 

 

 

 

M3 – 23,125

 

1,61,625

 

 

 

1,80,500

 

 

 

1,80,500

 2012

 

 

 

2013

 

 

 

Mar.31

Balance B/d

 

 

Jan 1

Depreciation A/c (WN5)

 

1,500

 

M1 – 96,000

 

Jan 1

Bank A/c (M1)

 

 6,000

 

M2 – 42,500

 

 

Jan 1

Profit and loss A/c

(Loss)

 

8,500

 

M3 – 23,125

 

1,61,625

Mar.31

Depreciation A/c

 

 

 

 

 

 

 

M1– 10,000

 

 

 

 

 

 

 

M2 – 5,000

 

 

 

 

 

 

 

M3 – 2,500

 

17,500

 

 

 

 

Mar.31

Balance c/d

 

 

 

 

 

 

 

M1 – 70,000

 

 

 

 

 

 

 

M2 – 37,500

 

 

 

 

 

 

 

M3 – 20,625

 

1,28,125

 

 

 

1,61,625

 

 

 

1,61,625

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Working notes:

WN 1: Annual depreciation @10% p. a.

Machinery 1 – 12,000 of 1,20,000

Machinery 2 – 5,000 of 50,000

Machinery 3 – 2,500 of 25,000

 

WN 2: First year depreciation @10% p. a.

Machinery 1 – 12,000 of 1,20,000

Machinery 2 – 5,000 of 50,000 for 6 month is 2,500

 

WN3: Depreciation (for 2nd Machinery)

(For 6 months) M2 – 2,500

Calculated as below

(1,20,000 ×10×6)÷(100×12) =2,500

 

WN4: Depreciation (for 3rd Machinery)

(For 9 months) M3 -1,875

Calculated as below

(50,000 ×10×9)÷(100×12) =1,875

 

WN5: Depreciation (for 1st machinery sold at time of sale)

(For Machinery, cost of 20,000 for 3 months)

Calculated as below

(25,000 ×10×3)÷(100×12) =1,500

 

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